SUPER UNIT
_{(Analog Command Input, High-Accuracy Type)}
Continuous and Short-time Rating Range

How to obtain the mean hydraulic power and root-mean-square pressure (example for single pump type)

When load pressure in each process within 1 cycle is P_n(n=1,2,...., n), flow rate is Q_n(n=1,2,...., n), and time is t_n(n=1,2,...., n)

• Mean hydraulic power＝(P₁×Q₁/60×t₁+P₂×Q₂/60×t₂+…+P_n×Q_n/60×t_n)/（t₁+t₂+…+tn)
  
• Root-mean-square of load pressure＝SQRT((P₁²×t₁+P₂²×t₂+…+Pn²×t²)/(t₁＋t₂+…+t_n)) (Note, however, that if the pump runs above the rated pump rotational speed of 1800 min^-1 to provide the control flow rate of Q_n, with the load pressure P_n, P_n needs to be converted to the value when the pump is running at 1800 min^-1.) When the pump capacity of the SUPER UNIT is q_n [cm³], the pump rotational speed N_n is N_n = Q_n×103/q_n. Therefore, converted pressure P_n = P_n×(N_n/1800)

Note 1:

The procedure for obtaining the mean hydraulic power and root-mean-square pressure with flow-rate-selection specifications (double pump type) is basically the same as above. Please consult us for detailed information.

Note 2:

SQRT above represents square root operation (√). For the continuous rating hydraulic powers for each model, see the pressure - flow rate characteristic charts (P-Q characteristic charts) given in the instruction manual provided separately.